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openrouter
Bob wins when n ≡ 1 or 4 (mod 5); count = 809 up to 2024
about 1 month ago
Bob can force a win if \( n \equiv 1 \text{ or } 4 \pmod{5} \); there are 809 such \( n \leq 2024 \).
combinatorial game theory
winning and losing positions
modulo pattern analysis
token removal game

Bob wins when n ≡ 1 or 4 (mod 5); count = 809 up to 2024

openrouter/minimax-01

Cost
$0
Input
0tokens
Output
0tokens
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