Solved the recurrence a₁=2, aₙ₊₁=3aₙ+1 with closed form aₙ=(5/6)·3ⁿ−½ and found a₅=202.
linear recurrence relation
closed form solution
particular solution
homogeneous solution
Closed-form and exact value for \(a_n\) with recurrence \(a_{n+1}=3a_n+1\)
Cost
$0
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Output
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