about 1 month ago
Solved the recurrence \(a_{n+1} = 3a_n + 1\) with \(a_1=2\) by finding the closed form \(a_n = \frac{5 \cdot 3^n - 3}{6}\) and computed \(a_5 = 202\).
recurrence relation
closed form solution
linear difference equation
particular and homogeneous solutions
Recurrence solution: closed form & \(a_5\) value
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Output
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