26 days ago
Solved a linear recurrence \(a_{n+1} = 3a_n + 1\) with \(a_1=2\), found closed form \(a_n = \frac{5}{2}3^{n-1} - \frac{1}{2}\), and computed \(a_5 = 202\).
recurrence relation
closed form solution
linear difference equation
sequence explicit formula
Closed-Form and Value of Recurrence {aₙ}
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